# C++ : Find Largest Element of an Array

Tutorial by:Manisha Dubey      Date: 2016-06-18 04:52:16

This program takes n number of element from user(where, n is specified by user) and stores data in an array. Then, this program displays the largest element of that array using loops.

## Source Code to Display Largest Element of an array

``````
#include <iostream>
using namespace std;
int main(){
int i,n;
float arr[100];
cout << "Enter total number of elements: ";
cin >> n;
cout << endl;
while (n>100 || n<=0)
{
cout << "Error! number should in range of (1 to 100)." << endl;
cout << "Enter the number again: ";
cin >> n;
}
for(i=0;i<n;++i)  /* Stores number entered by user. */
{
cout << "Enter Number " << i+1 << " : ";
cin >> arr[i];
}
for(i=1;i<n;++i)  /* Loop to store largest number to arr[0] */
{
if(arr[0]<arr[i]) /* Change < to > if you want to find smallest element*/
arr[0]=arr[i];
}
cout << "Largest element = " << arr[0];
return 0;
}``````

Output

```
Enter total number of elements: 8

Enter Number 1: 23.4
Enter Number 2: -34.5
Enter Number 3: 50
Enter Number 4: 33.5
Enter Number 5: 55.5
Enter Number 6: 43.7
Enter Number 7: 5.7
Enter Number 8: -66.5

Largest element = 55.5
```

This program takes n number of elements from user and stores it in array arr[]. To find the largest element, the first two elements of array are checked and largest of these two element is placed in arr[0]. Then, the first and third elements are checked and largest of these two element is placed in arr[0]. This process continues until and first and last elements are checked. After this process, the largest element of an array will be in arr[0] position.

## C++

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