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C++ : Display Factors of a Number

Tutorial by:Manisha Dubey      Date: 2016-06-18 04:25:05

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This program takes a positive integer from an user and displays all the factors of that number.

Source Code to Display Factors of a Number


/* C++ to find and display all the factors of a number entered by an user.. */

#include <iostream>
using namespace std;
int main()
{
  int n,i;
  cout << "Enter a positive integer: ";
  cin >> n;
  cout << "Factors of " << n << " are: " << endl;  
  for(i=1;i<=n;++i)
  {
      if(n%i==0)
         cout << i << endl;
  }
  return 0;
}

Output

Enter a positive integer: 60
Factors of 60 are: 1 2 3 4 5 6 12 15 20 30 60

 

 
 

In this program, an integer entered by user is stored in variable n. Then, for loop is executed with initial condition i=1 and checked whether n is perfectly divisible by i or not. If n is perfectly divisible by i then, i will be the factor of n. In each iteration, the value of i is updated(increased by 1). This process goes until test condition i<=n becomes false,i.e., this program checks whether number entered by user n is perfectly divisible by all numbers from 1 to n and all displays factors of that number.

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C++

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