# C++ : Check Whether Number is Even or Odd

Tutorial by:Manisha Dubey      Date: 2016-06-18 03:29:45

Integers which are perfectly divisible by 2 are called even numbers. And those integers which are not perfectly divisible by 2 are not known as odd number. To check whether an integer is even or odd, the remainder is calculated when it is divided by 2 using modulus operator %. If remainder is zero, that integer is even if not that integer is odd.

``````
#include <iostream>
using namespace std;

int main() {
int n;
cout << "Enter an integer: ";
cin >> n;
if ( n%2 == 0) {
cout << n << " is even.";
}
else {
cout << n << " is odd.";

}
return 0;
}``````

Output

```Enter an integer: 23
23 is odd.```

In this program, if..else statement is used to check whether `n%2 == 0` is true or not. If this expression is true, n is even if not n is odd.

You can also use ternary operators ?: instead of if..else statement. Ternary operator is short hand notation of if...else statement.

``````#include <iostream>
using namespace std;

int main() {
int n;
cout << "Enter an integer: ";
cin >> n;

(n%2 == 0) ? cout << n << " is even." :  cout << n << " is odd.";

return 0;
}``````

## C++

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